Answer
$ \frac{x^2(4x-15)}{(2x-5)^2}$
Work Step by Step
$\frac{(2x-5)\cdot3x^2-x^3\cdot2}{(2x-5)^2}=\frac{6x^3-15x^2-2x^3}{(2x-5)^2}=\frac{x^2(4x-15)}{(2x-5)^2}$
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