Answer
$ \frac{-x^3-3x^2+2x-1}{x^2(x-1)^2}$
Work Step by Step
$\frac{x}{(x-1)^2}+\frac{2}{x}-\frac{x+1}{x^3-x^2}=\frac{x}{(x-1)^2}+\frac{2}{x}-\frac{x+1}{x^2(x-1)}=\frac{x^3+2x(x-1)^2+(x+1)(x-1)}{x^2(x-1)^2}=\frac{-x^3-3x^2+2x-1}{x^2(x-1)^2}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A54: 70
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