Answer
$ \frac{3x-1}{2x+1}$
Work Step by Step
$\frac{2(x-1)^{-1}+3}{3(x-1)^{-1}+2}=\frac{2(x-1)^{-1}+3}{3(x-1)^{-1}+2}\times\frac{x-1}{x-1}=\frac{2+3(x-1)}{3+2(x-1)}=\frac{3x-1}{2x+1}$
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