Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A54: 83

Answer

$ \frac{3x-1}{2x+1}$

Work Step by Step

$\frac{2(x-1)^{-1}+3}{3(x-1)^{-1}+2}=\frac{2(x-1)^{-1}+3}{3(x-1)^{-1}+2}\times\frac{x-1}{x-1}=\frac{2+3(x-1)}{3+2(x-1)}=\frac{3x-1}{2x+1}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.