Answer
$ \frac{x^2+4}{(x+2)^2(x-2)^2}$
Work Step by Step
$\frac{x\cdot2x-(x^2-4)\cdot1}{(x^2-4)^2}=\frac{2x^2-x^2+4}{(x^2-4)^2}=\frac{x^2+4}{(x+2)^2(x-2)^2}$
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