Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A54: 75

Answer

$\frac{(x+1)(x-1)}{2x(2x+1)}$

Work Step by Step

$\frac{2-\frac{x+1}{x}}{3+\frac{x-1}{x+1}}=\frac{2-\frac{x+1}{x}}{3+\frac{x-1}{x+1}}\times\frac{x(x+1)}{x(x+1)}=\frac{2x(x+1)-(x+1)^2}{3x(x+1)-x(x-1)}=\frac{(x+1)(x-1)}{2x(2x+1)}$
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