Answer
$\frac{(x+1)(x-1)}{2x(2x+1)}$
Work Step by Step
$\frac{2-\frac{x+1}{x}}{3+\frac{x-1}{x+1}}=\frac{2-\frac{x+1}{x}}{3+\frac{x-1}{x+1}}\times\frac{x(x+1)}{x(x+1)}=\frac{2x(x+1)-(x+1)^2}{3x(x+1)-x(x-1)}=\frac{(x+1)(x-1)}{2x(2x+1)}$
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