Answer
$ \frac{-x^2+3x+13}{(x+4)(x+1)(x-2)}$
Work Step by Step
$\frac{x+4}{x^2-x-2}-\frac{2x+3}{x^2+2x-8}=\frac{x+4}{(x+1)(x-2)}-\frac{2x+3}{(x+4)(x-2)}=\frac{(x+4)^2-(2x+3)(x+1)}{(x+4)(x+1)(x-2)}=\frac{-x^2+3x+13}{(x+4)(x+1)(x-2)}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A54: 67
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