Answer
$ \frac{x^3-2x^2+4x+3}{x^2(x-1)(x+1)}$
Work Step by Step
$\frac{1}{x}-\frac{2}{x^2+x}+\frac{3}{x^3-x^2}=\frac{1}{x}-\frac{2}{x(x+1)}+\frac{3}{x^2(x-1)}=\frac{x(x-1)(x+1)-2x(x-1)+3(x+1)}{x^2(x-1)(x+1)}=\frac{x^3-2x^2+4x+3}{x^2(x-1)(x+1)}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A54: 69
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