Answer
$ \frac{19}{(3x-5)^2}$
Work Step by Step
$\frac{(2x+3)\cdot3-(3x-5)\cdot2}{(3x-5)^2}=\frac{6x+9-(6x-10)}{(3x-5)^2}=\frac{19}{(3x-5)^2}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A54: 85
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