Answer
See below.
Work Step by Step
$LHS=\frac{(1+sin\theta)^2-(1-sin\theta)^2}{(1-sin\theta)(1+sin\theta)}=\frac{4sin\theta}{1-sin^2\theta}=\frac{4sin\theta}{cos^2\theta}=4tan\theta sec\theta=RHS$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 76
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