Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 40

Answer

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Work Step by Step

$LHS=\frac{1}{sin(u)}-\frac{cos(u)}{sin(u)}=\frac{1-cos(u)}{sin(u)}=\frac{1-cos(u)}{sin(u)}\times\frac{1+cos(u)}{1+cos(u)}=\frac{1-cos^2(u)}{sin(u)(1+cos(u))}=\frac{sin^2(u)}{sin(u)(1+cos(u))}=\frac{sin(u)}{1+cos(u)}=RHS$
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