Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 63

Answer

See explanations.

Work Step by Step

$LHS=\frac{sin\theta/cos\theta-cos\theta/sin\theta}{sin\theta/cos\theta+cos\theta/sin\theta}\times\frac{sin\theta cos\theta}{sin\theta cos\theta}=\frac{sin^2\theta-cos^2\theta}{sin^2\theta+cos^2\theta}=sin^2\theta-cos^2\theta=RHS$
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