Answer
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Work Step by Step
$LHS=\frac{sin\theta cos\theta}{cos^2\theta-sin^2\theta}\times\frac{1/cos^2\theta}{1/cos^2\theta}=\frac{sin\theta/cos\theta}{1-sin^2\theta/cos^2\theta}=\frac{tan\theta}{1-tan^2\theta}=RHS$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 60
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