Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 44

Answer

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Work Step by Step

$LHS=\frac{1-cos\theta-sin^2\theta}{1-cos\theta}=\frac{-cos\theta+cos^2\theta}{1-cos\theta}=\frac{-cos\theta(1-cos\theta)}{1-cos\theta}=-cos\theta=RHS$
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