Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 48

Answer

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Work Step by Step

$LHS=\frac{csc\theta-1}{cot\theta}\times\frac{csc\theta+1}{csc\theta+1}=\frac{csc^2\theta-1}{cot\theta(csc\theta+1)}=\frac{cot^2\theta}{cot\theta(csc\theta+1)}=\frac{cot\theta}{csc\theta+1}=RHS$
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