Answer
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Work Step by Step
$LHS=\frac{1+cos\theta-sin^2\theta}{1+cos\theta}=\frac{cos\theta+cos^2\theta}{1+cos\theta}=\frac{cos\theta(1+cos\theta)}{1+cos\theta}=cos\theta=RHS$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 54
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