Answer
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Work Step by Step
$LHS=\frac{1+sin\theta-cos^2\theta}{1+sin\theta}=\frac{sin\theta+sin^2\theta}{1+sin\theta}=\frac{sin\theta(1+sin\theta)}{1+sin\theta}=sin\theta=RHS$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 43
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