Answer
$\frac{1}{sin\theta cos\theta}$
Work Step by Step
$\frac{sin\theta+cos\theta}{cos\theta}+\frac{cos\theta-sin\theta}{sin\theta}=\frac{sin^2\theta+sin\theta cos\theta+cos^2\theta-sin\theta cos\theta}{sin\theta cos\theta}=\frac{1}{sin\theta cos\theta}$
