Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A30: 118

Answer

$(5x)(25x^2+15x+3)$

Work Step by Step

Write $1$ as $1^3$: $(5x+1)^3-1=(5x+1)^3-1^3$ Use the special formula $a^3-b^3=(a-b)(a^2+ab+b^2)$ where $a=(5x+1)$ and $b=1$. $=[(5x+1)-1][(5x+1)^2+(5x+1)(1)+1^2]$ Simplify. $=(5x)[(5x+1)^2+5x+1+1]$ $=(5x)[(5x+1)^2+5x+2]$ Use the special formula $(a+b)^2=a^2+2ab+b^2$ where $a=5x$ and $b=1$. $=(5x)[(5x)^2+2(5x)(1)+(1)^2+5x+2]$ Simplify. $=(5x)[25x^2+10x+1+5x+2]$ $=(5x)(25x^2+15x+3)$ Hence, the completely factored form of the given expression is $(5x)(25x^2+15x+3)$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.