Answer
$-(16x+5)(x-1)$
Work Step by Step
Write the given expression in standard form:
$5+11x-16x^2=-16x^2+11x+5$
Factor out $-1$:
$-16x^2+11x+5\\
=-1(16x^2-11x-5)\\
=-(16x^2-11x-5)$
Rewrite $-11x$ as $5x-16x$.
$=-(16x^2+5x-16x-5)$
Group the first two terms together and group the last two terms together.
$=-[(16x^2+5x)+(-16x-5)]$
Factor out $x$ in the first group and $-1$ in the second group.
$=-[x(16x+5)+(-1)(16x+5)]$
$=-[x(16x+5)-(16x+5)]$
Factor out $(16x+5)$.
$=-(16x+5)(x-1)$
Hence, the complete factor form is $-(16x+5)(x-1)$.
