Answer
$8\pi$
Work Step by Step
Step 1. Draw a diagram as shown in the figure. The limits of integration with respect to $x$ can be found as from $0$ to $2$.
Step 2. Approximate using cylinders; we have $dV=2\pi x(x^2-0) dx=2\pi x^3\ dx$
Step 3. We have
$V=\int_0^2 2\pi x^3\ dx=\frac{\pi}{2}x^4|_0^2=8\pi$