Answer
$f'(x) = \frac{2}{\sqrt {1-4x^2}}$
Work Step by Step
$f(x) = \sin^{-1}(2x)$
Chain Rule:
$f'(x) = 2 \times \frac{1}{\sqrt {1-(2x)^2}} = \frac{2}{\sqrt {1-4x^2}}$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - 3.10 Derivatives of Inverse Trigonometric Functions - 3.10 Execises - Page 221: 7
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