Answer
Slope of Tangent Line: $\frac{1}{5}$
Work Step by Step
$f(x) = \tan^{-1}(x)$
$f'(x) = \frac{1}{1+x^2}$
$f'(-2)=\frac{1}{1+(-2)^2} = \frac{1}{5}$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - 3.10 Derivatives of Inverse Trigonometric Functions - 3.10 Execises - Page 221: 3
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