Answer
The planar vector fields satisfies by the $\bf{Plot (A)}$.
Work Step by Step
When we draw a vector field , we need to draw $F(P)$ as a vector based at a point (let us say a point) $P$. The domain of $F$ corresponds to the set of points $P$ for which $F(P)$ is defined.
This follows that $F(x,y)=\lt x+y, x-y \gt \quad \text{and} \quad F=(x+y) \ i+(x-y) \ j$
Thus, when we draw a vector field of $F$ at any point the vector will be directed to $(x+y) \ i+(x-y) \ j$ direction.
For each point $(a,b)$, we have: $-2 \leq a\leq 2, -2 \leq b \leq 2$
So, we interpret from the above discussion that the planar vector fields satisfies by the $\bf{Plot (A)}$.
