Answer
$\frac{2}{3(x-1)(x+1)}$
Work Step by Step
$y=ln \sqrt[3] \frac{x-1}{x+1}$
$=ln (\frac{x-1}{x+1})^{1/3}$
$=\frac{1}{3}ln(\frac{x-1}{x+1})$
$=\frac{1}{3}(ln(x-1)-ln(x+1))$
$=\frac{1}{3}(\frac{1}{x-1}-\frac{1}{x+1})$
$=\frac{1}{3}(\frac{x+1-x+1}{(x-1)(x+1)})$
$=\frac{2}{3(x-1)(x+1)}$
