Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.1 Exercises - Page 325: 26

Answer

$2+ln(3)$

Work Step by Step

Use the rule that $log(ab)=log(a)+log(b)$ to expand the logarithm into $ln(e^{2})+2$. Next, use the fact that $log(x^{n})=nlog(x)$ to expand the logarithmic expression into $2ln(e)+ln(3)$. Finally, use the fact that $ln(e)=1$ to simplify the expression to $2+ln(3)$.
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