Answer
please see image
Work Step by Step
1. Start by sketching $f_{1}(x)=\ln x$
2. $f_{2}=f_{1}(x-3)=\ln( x-3)$
(shift $f_{1}$ 3 units to the right)
Its domain is $x>3.$
(screenshot included)
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.1 Exercises - Page 325: 13
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