Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.1 Exercises - Page 325: 17

Answer

a. $1.7917$ b. $-0.4055$ c. $4.3944$ d. $0.5493$

Work Step by Step

$a.\ \ \ln 6=\ln (2\cdot 3)=\ln 2+\ln 3$$\approx 0.6931+1.0986=1.7917$ $b.\displaystyle \ \ \ln\frac{2}{3}=\ln 2-\ln 3\approx 0.6931-1.0986=-0.4055$ $c.\ \ \ln 81=\ln 3^{4}=4\ln 3\approx 4(1.0986)=4.3944$ $d. \displaystyle \ \ \ln\sqrt{3}=\ln 3^{1/2}=\frac{1}{2}\ln 3\approx\frac{1}{2}(1.0986)=0.5493$
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