Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.1 Exercises - Page 251: 8

Answer

$-\frac{1}{4x}+C$

Work Step by Step

Given: $\int \frac{1}{4x^{2}}dx$ Rewrite: $\frac{1}{4}\int x^{-2}dx$ Integrate: $\frac{1}{4}(\frac{x^{-1}}{-1})+C$ Simplify: $-\frac{1}{4x}+C$
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