Answer
$-\frac{1}{4x}+C$
Work Step by Step
Given:
$\int \frac{1}{4x^{2}}dx$
Rewrite:
$\frac{1}{4}\int x^{-2}dx$
Integrate:
$\frac{1}{4}(\frac{x^{-1}}{-1})+C$
Simplify:
$-\frac{1}{4x}+C$
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