Answer
$\int (\sqrt[4]{x^3}+1)dx=\dfrac{4}{7\sqrt[4]{x}}+x+C.$
Work Step by Step
$\int (\sqrt[4]{x^3}+1)dx=\int x^{\frac{3}{4}}dx+\int1 dx=\dfrac{4}{7\sqrt[4]{x}}+x+C.$
By differentiating, we get the same integrand we started with.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.1 Exercises - Page 251: 18
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