Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.1 Exercises - Page 251: 44

Answer

y=$\frac{1}{x}$+2

Work Step by Step

$\frac{dy}{dx}$= $-x^{-2}$ $\int\frac{dy}{dx}$=$\int-x^{-2}$ y = $\frac{-x^{-1}}{-1}$ + c y = $\frac{1}{x}$ + c Using the point (1,3), the particular solution can be found 3 = $\frac{1}{1}$ + c c = 2 Plug in c to the general solution y=$\frac{1}{x}$+2
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