Answer
$3x^{2}$ + $8$
Work Step by Step
$f'(x)$ = $6x$
$f(x)$ = $\int$$f'(x)$$dx$
$f(x)$ = $\int$$6x$$dx$
$f(x)$ = $3x^{2}$ + $c$
$f(0)$ = $8$
$3(0)^{2}$ + $c$ = $8$
$c$ = $8$
so $f(x)$ = $3x^{2}$ + $8$
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