Answer
$-\frac{1}{9x}+C$
Work Step by Step
Given:
$\int \frac{1}{(3x)^{2}}dx$
Rewrite:
$=\int \frac{1}{9x^{2}}dx$
$=\frac{1}{9}\int x^{-2}dx$
Integrate:
$=\frac{1}{9}(\frac{x^{-1}}{-1})+C$
Simplify:
$=-\frac{1}{9x}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.1 Exercises - Page 251: 10
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