Answer
$ y $ = $ 5t + C $
Work Step by Step
$\frac{dy}{dt} $ = $ 5 $
To get the original equation, we have to integrate the aforementioned differential equation.
$y=\int dy=\int5 dt$
= $\int5t^{0} dt$
= $\frac{5t^{0+1}}{1} + C $
= $ 5t^{1} + C $
= $ 5t + C $
Hence, $ y $ = $ 5t + C $
