Answer
$\frac{1}{2}x^{2} + 7x + C $
Work Step by Step
$\int (x+7) dx $
= $\int x dx + \int 7 dx $
= $\frac{x^{1+1}}{1+1} + C'+ \int 7x^{0} dx $
= $\frac{x^{2}}{2} + \frac{7x^{1}}{1} + C $
= $\frac{1}{2}x^{2} + 7x + C $
The result can be checked by differentiating, and it works.
