Answer
$= \frac{16}{5}t^{5} + 8t^{3} + 9t + C$
Work Step by Step
$\int (4t^{2}+3)^{2}dt$
$\int (4t^{2}(4t^{2} + 3) + 3(4t^{2} + 3)) dt$
$\int (16t^{4} + 12t^{2} + 12t^{2} + 9)dt$
$\int (16t^{4} + 24t^{2} + 9) dt$
$= \frac{16t^{5}}{5} + \frac{24t^{3}}{3} + 9t + C$
$= \frac{16}{5}t^{5} + 8t^{3} + 9t + C$
