Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.1 Exercises - Page 251: 5

Answer

$ y $ = $ \frac{2}{5}x^{\frac{5}{2}} + C $

Work Step by Step

$\frac{dy}{dx} $ = $ x^{\frac{3}{2}}$ To get the original equation, we have to integrate the aforementioned differential equation. $y=\int dy=\int x^{\frac{3}{2}} dx$ = $\frac{x^{{\frac{3}{2}}+1}}{{\frac{3}{2}}+1} + C $ = $ \frac{x^{\frac{5}{2}}}{\frac{5}{2}} + C $ = $ \frac{2x^{\frac{5}{2}}}{5} + C $ = $ \frac{2}{5}x^{\frac{5}{2}} + C $ Hence, $ y $ = $ \frac{2}{5}x^{\frac{5}{2}} + C $ The result checks out by differentiation.
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