Answer
$= x^{3} + \frac{1}{2}x^{2} - 2x +C $
Work Step by Step
$\int (x+1)(3x-2) dx$
$\int (x(3x-2)+1(3x-2))dx$
$\int (3x^{2} - 2x + 3x - 2) dx$
$\int (3x^{2} + x - 2) dx$
$= \frac{3x^{3}}{3} + \frac{x^{2}}{2} - 2x + C$
$= x^{3} + \frac{1}{2}x^{2} - 2x +C $
