Answer
$a(x-4)(x-11)$
Work Step by Step
$ax^2-15ax+44a\longrightarrow$ a is a common factor.
$a(x^2-15x+44)$
=$a(\ \ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ \ )$
=$a(x\ \ \ \ \ \ \ )(x\ \ \ \ \ \ \ )$
=$a(x-\ \ )(x-\ \ )$ Since the 2nd term is negative and the 3rd is positive, both factors or 44 must be negative
=$a(x-4)(x-11)$ -4 and -11 have a sum of -15 and a product of 44.
