Answer
$(x+4)(x-2)$
Work Step by Step
$x^2+2x-8$ has no common monomial factor.
$x^2+2x-8=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$
$x^2+2x-8=(x\ \ \ \ \ \ )(x\ \ \ \ \ \ )$
$x^2+2x-8=(x+\ )(x-\ )$ The factors of -8 must have unlike signs.
$x^2+2x-8=(x+4)(x-2)$ 4 and -2 have a sum of 2 and a product of -8.
