Answer
$(x+3)(x-5)$
Work Step by Step
$x^2-2x-15$ has no common monomial factor.
$x^2-2x-15=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$
$x^2-2x-15=(x\ \ \ \ \ \ )(x\ \ \ \ \ \ )$
$x^2-2x-15=(x+\ )(x-\ )$ The factors of -15 must have unlike signs.
$x^2-2x-15=(x+3)(x-5)$ 4 and -2 have a sum of 2 and a product of -8.
