Answer
$(y+3)(y+14)$
Work Step by Step
$y^2+17y+42$ has no common monomial factor
$=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$
$=(y\ \ \ \ \ \ )(y\ \ \ \ \ \ )$
$=(y+\ )(y+\ )$ All signs in the trinomial are positive.
$=(y+3)(y+14)$ 3 and 14 have a sum of 17 and a product of 42.
6 and 7 have a product of 42, but their sum is only 13. 42 is not divisible by 5 or 4, so the next factor to check is 3.
