Answer
$(y-2)(y-16)$
Work Step by Step
$y2-18y+32$ has no common monomial factor
=$(\ \ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ \ )$
=$(y\ \ \ \ \ \ \ )(y\ \ \ \ \ \ \ )$
=$(y-\ \ )(y-\ \ )$ Since the 2nd term is negative and the 3rd is positive, the factors of 32 must both be negative.
=$(y-2)(y-16)$ -2 and -16 have a sum of -18 and a product of 32.
