Answer
$(y-4)(y-10)$
Work Step by Step
$y^2-14y+40$ has no common monomial factor
$=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$
$=(y\ \ \ \ \ \ )(y\ \ \ \ \ \ )$
$=(y+\ )(y-\ )$ Since the 2nd term is negative and the 3rd is positive, both factors of 40 must be negative.
$=(y-4)(y-10)$ -4 and -10 have a sum of -14 and a product of 40.
