Answer
$(m-2)(m-20)$
Work Step by Step
$m^2-22m+40$ has no common monomial factor
$=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$
$=(m\ \ \ \ \ \ )(m\ \ \ \ \ \ )$
$=(m-\ )(m-\ )$ Since the 2nd term is negative and the 3rd positive, the two factors of 40 must both be negative.
$=(m-2)(m-20)$ -2 and -20 have a sum of -22 and a product of 40.
