Answer
$(a+7)(a-2)$
Work Step by Step
$a^2+5a-14$ has no common monomial factor
$=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$
$=(a\ \ \ \ \ \ )(a\ \ \ \ \ \ )$
$=(a+\ )(a-\ )$ The factors of -14 must have unlike signs.
$=(a+7)(a-2)$ 7 and -2 have a sum of 5 and a product of -14.
