Answer
$2(w+2)(w-8)$
Work Step by Step
$2w^2-12w-32\longrightarrow$ 2 is a common factor.
$=2(w^2-6w-16)$
$=2(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$
$=2(w\ \ \ \ \ \ )(w\ \ \ \ \ \ )$
$=2(w+\ )(w-\ )$ The factors of -32 must have unlike signs.
$=2(w+2)(w-8)$ 2 and -8 have a sum of -6 and a product of -16.
