Answer
$(x+4)(x+14)$
Work Step by Step
$x^2+18x+56$ has no common monomial factors.
=$(\ \ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ \ )$
=$(x\ \ \ \ \ \ \ )(x\ \ \ \ \ \ \ )$
=$(x+\ \ )(x+\ \ )$ All terms in the trinomial are positive.
=$(x+4)(x+14)$ 4 and 14 have a sum of 18 and a product of 56.
