Answer
$(y+5)(y-19)$
Work Step by Step
$y2-14y-95$ has no common monomial factor
=$(\ \ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ \ )$
=$(y\ \ \ \ \ \ \ )(y\ \ \ \ \ \ \ )$
=$(y+\ \ )(y-\ \ )$ The factors of -95 must have unlike signs.
=$(y+5)(y-19)$ 5 and -19 have a sum of -14 and a product of -95.
