Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise - Page 350: 71

Answer

$(x-9)(x-17)$

Work Step by Step

We need to factor: $x^2-26x+153$ The first term in each binomial must be $x$, since $x^2$ has no coefficient. The operation in each binomial is subtraction since the last term in the trinomial is positive and the second is negative. Since $-9-17=-26$ and $(-9)(-17)=153$, the other two terms are $ -9$ and $-17$. Thus, we have: $x^2-26x+153=(x-9)(x-17)$
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