Answer
$(x-3)(x-5)$
Work Step by Step
$x^2-8x+15$ has no common monomial factor
$=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$
$=(x\ \ \ \ \ \ )(x\ \ \ \ \ \ )$
$=(x-\ )(x-\ )$ Since the 2nd term is negative and the 3rd is positive, both factors of 15 must be negative.
$=(x-3)(x-5)$ -3 and -5 have a sum of -8 and a product of 15.
